a=lim(n→∞) [ (1^p+2^p+3^p+...+n^p)/n^(p+1) ]
b=lim(n→∞) [ (1^p+2^p+3^p+...+n^p)/n^p - an ]
c=lim(n→∞) [ (1^p+2^p+3^p+...+n^p)/n^(p-1) - an² - bn ],
find a, b and c =?
圖片參考：http://imgcld.yimg.com/8/n/HA06881079/o/701108070113213873438740.jpg
更新1:
In fact, it is sufficient for any constants p > 1 (not necessarily for integer p).
