求積分的正確值
1. ∫ (sinx-cosx)/(3sin²x - 4sinx cosx + 6cos²x) dx
2. ∫_[0,π] (sinx-cosx)/(3sin²x - 4sinx cosx + 6cos²x) dx
圖片參考：http://imgcld.yimg.com/8/n/HA06881079/o/101108070905413869404360.jpg
求兩題積分
2011-08-08 6:08 am
回答 (3)
2011-08-13 9:07 pm
2011-08-09 2:58 am
{√2 arctan(√2) + (3/√7) ln[(4+√7)/3] } / 5
2011-08-08 6:26 pm
t-substitution:
let tan x/2 = t...
then integrate it using partial fractions
let tan x/2 = t...
then integrate it using partial fractions
收錄日期: 2021-04-23 23:27:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110807000010KK09054