這條問題THXXXX好難

2011-08-05 5:56 am
what is the percentage change in the volume of a gas that is heated from S.T.P to 85C eheras its preesure is doubled



what is the root-mean quare speed of a sample of helium gas at 25C at a preesure of 100KPA

(given:molar mass of helium =4,0G MOL^-1)

PS: 4.0GMOL^-1洗唔洗轉KG?
更新1:

eheras=WHEHERAS

回答 (1)

2011-08-05 7:14 am
✔ 最佳答案
1. Using iseal gas equation PV/T = constant
hence, (1 x Vo)/273 = 2 x V/(273+85)
where Vo and V are the initial and final volume of the gas
hence, V/Vo = (273+85)/(2 x 273) = 0.656
Percentage change in volume
= [(V - Vo)/Vo] x 100% = [(V/Vo - 1)] x 100% = (0.656-1) x 100% = -34.4%

The gas has reduced in volume by 34.4%

2. Since molar mass of helium = 4 g/mol, and 1 mole of any gas occupies 22.4 L at STP (Avogadro's hypothesis)

Volume of 1 mole of gas at 25'C, using ideal gas law, is= [(273+25)/273] x 22.4 L = 24.45 L = 0.0245 m^3

Density of gas at 25'C = 4/0.0245 g/m^3 = 163.26 g/m^3 = 0.163 kg/m^3

hence, rms speed = square-root[3 x pressure/density]i.e. rms speed = square-root[ 3 x 10^5/0.163] m/s = 1357 m/s


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