另一條關於electric circuit的phy問題

👨🏻‍🏫 學術台其他 - 科學

Christopher

2011-08-02 1:06 am

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What are the current I(1) flowing through the 10 ohm resistor and the current I2 flowing through the 5 ohm resistor?

更新1:

@天同咁可唔可以consider 2V battery 同 5 ohm resistor去計個I2?

回答 (2)

天同

2011-08-02 4:24 am

✔ 最佳答案

First, consider the "large loop" that consists of the two batteries

2 - 1.5 = 10(I1)
i.e. I1 = 0.5/10 A = 0.05 A

Consider the loop with the 1.5v battery and the 5-ohm resistor
1.5 = (I2).(5)i.e. I2 = 1.5/5 A = 0.3 A

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用戶8430

2011-08-02 4:52 am

由於電路兩端係1.5V, 所以I(2)只可以用1.5V來計算, 除非你將個1.5V電池搬走, 你就可以直接用2V來計算, 即係 :
I = V / (R1 + R2)

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