Permutations

the number of ways that 8 different flowers can be formed is 8x7x6x5x4x3x2x1=8!

since the flower will be threaded to form a circular wreath, so the actually number of ways =8!/8 =7! (just because f1,f2,f3...f8 = f2,f3...f8,f1 = ...=f8,f1...f7)

Since the wreath can be viewed from both sides, so the actual number of ways=7!/2 (since f1,f2,f3,f4,f5,f6,f7,f8 can be viewed as equal as f8,f7,f6,f5,f4,f3,f2,f1)

the answer is 7!/2

希望幫到你！

002 的 7!/2 對

There are totally

8x7x6x...x1

= 8! methods

For A wreath can be viewed from both sides:

e.g. 12345678 and 87654321 is included in those 8! methods

So, it's no need to times 2.