ce mcq maths

2011-07-25 1:22 am

圖片參考:http://imgcld.yimg.com/8/n/HA00095355/o/701107240065013873432110.jpg


圖片參考:http://imgcld.yimg.com/8/n/HA00095355/o/701107240065013873432121.jpg


i want to know how to do this 3 questions ( they are ce mcq)

回答 (1)

2011-07-25 3:23 am
✔ 最佳答案
8)

α , β are the roots of 3x² - hx - b = 0

α + β = (- -h) / 3 = h/3

Answer : (C)



11)

275°......十 A
..........∕ 75°
十 B


180 + 75 = 225°

Answer : (E)


12)

Let a be the 1st term , r be the common ratio :

a / (1 - r) = 81/4
a = (81/4)(1 - r) .....(1)

ar = - 9 .....(2)


Sub (1) into (2) :

(81/4)(1 - r) r = - 9

9(r - 1)r = 4

9r² - 9r - 4 = 0

(3r - 4)(3r + 1) = 0

r = 4/3 (rejected since - 1 < r < 1) or r = - 1/3

Answer : (A)




2011-07-24 19:30:24 補充:
Q11) Typing error :

275° should be 255°

2011-07-24 19:31:05 補充:
and 225° should be 255°


收錄日期: 2021-04-21 22:22:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110724000051KK00650

檢視 Wayback Machine 備份