maths.trigonometry

2011-07-23 1:44 am
A chord of length 8cm divides a circle of radius 5cm into two parts.Find the area of each part.

回答 (1)

2011-07-23 4:27 am
✔ 最佳答案
Let half of the subtended angle of the minor circle is x

sin x = 4/5 => x = 53.13 = 0.9273 rad

So, the area of the minor part

= (1/2)(5^2)(1.8546)

= 23.1825 cm^2

The area of the larger part

= (1/2)(5^2)(4.4286)

= 55.3573 cm^2



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