maths.trigonometry

Let half of the subtended angle of the minor circle is x

sin x = 4/5 => x = 53.13 = 0.9273 rad

So, the area of the minor part

= (1/2)(5^2)(1.8546)

= 23.1825 cm^2

The area of the larger part

= (1/2)(5^2)(4.4286)

= 55.3573 cm^2