Mathes Inequalities

2011-07-21 6:47 am
1. A second hand car showroom has a space of 420 m^2 for displaying two different models of cars: a family car and a sport car. A family car needs 8 m^2 of space and a sports car needs 10 m^2 of space for display. The cost for displaying a family car and a sport car is $300 and $600 respectively. The total cost for the display should not exceed $18000. Asume that there are x family cars and y sports cars displayed.
The constraints are: 8x+10y(<=)420...(1)
300x+600y<=18000...(2)
x and y are non negative integers...(3)
The net profit on selling a family car and a sport car is $6000 and $10000 respectively. Asume that all the cars displayed will be sold. 40 family cars should be displayed to get the maximum profit $340000. (If the number of family cars sold is at least five times the number of sports cars sold, find the maximum profit and the corresponding number of family cars sold)

回答 (1)

2011-07-21 3:14 pm
✔ 最佳答案
There is one more constraint : x > 5y.
Max. profit happens at the intersection of x = 5y and 8x + 10y < 420. That is x = 42 and y = 8.4.
Since x and y must be integer, so x = 42 and y = 8.
Max. profit = 42 x 6000 + 8 x 10000 = $332,000.


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