f(x) = 2^x and g(x) = 2^(x+1) , then f(4y) - g(y - 1) = ?
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Maths (Functions and Graphs )
2011-07-21 5:52 am
回答 (2)
2011-07-21 6:45 am
2011-07-21 6:39 am
f(4y) = 2^(4y) = 16^y
g(y-1) = 2^[(y-1)+1] = 2^y
f(4y) - g(y-1)
= 16^y - 2^y
g(y-1) = 2^[(y-1)+1] = 2^y
f(4y) - g(y-1)
= 16^y - 2^y
收錄日期: 2021-04-23 20:44:59
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https://hk.answers.yahoo.com/question/index?qid=20110720000051KK01229