Find the no. of roots of the equation 6sinxcosx+3sinx-2cosx-1=0 for 0<=x<=360.
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F.5 maths
2011-07-21 4:18 am
回答 (1)
2011-07-21 5:24 am
✔ 最佳答案
2cosx(3sinx - 1) + (3sinx - 1) = 0(3sinx - 1)(2cosx + 1) = 0
sin x = 1/3 ...............(1)
cosx = - 1/2 ..............(2)
For 0 < x < 360, (1) has 2 roots, (2) has 2 roots, so total 4 roots.
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