ce maths
回答 (2)
2011-07-19 4:52 am
✔ 最佳答案
(1/x² + 1/y²) / (1/x +1/y )(y²/x²y² + x²/x²y²) / (y/xy +x/xy )
= [(x² + y²)/x²y²] / [(x + y)/xy]
= [(x² + y²)/x²y²] * [xy/(x + y)]
= (x² + y²) /xy(x + y)
2011-07-18 20:52:55 補充：
發問時，點數已付出。刪除答案，只會損人不利己。
2011-07-22 00:35:48 補充：
謝謝樓下的坦白，連抄襲我也註明出處。
參考: 土扁, 土扁
2011-07-20 1:39 am
(1/x² + 1/y²) / (1/x +1/y )
=(y²/x²y² + x²/x²y²) / (y/xy +x/xy )
= [(x² + y²)/x²y²] / [(x + y)/xy]
= [(x² + y²)/x²y²] * [xy/(x + y)]
= (x² + y²) /xy(x + y)
=(y²/x²y² + x²/x²y²) / (y/xy +x/xy )
= [(x² + y²)/x²y²] / [(x + y)/xy]
= [(x² + y²)/x²y²] * [xy/(x + y)]
= (x² + y²) /xy(x + y)
參考: 上面
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