MATHS~~~~~~~~~~~~~~~~~~
2011-07-17 9:53 pm
回答 (1)
2011-07-17 10:23 pm
✔ 最佳答案
弧AD : 弧DC : 弧CB : 弧BA = 2 : 1 : 1 : 1ㄥACD : ㄥDBC : ㄥCDB : ㄥBCA = 2 : 1 : 1 : 1 (等弧,等角)令 ㄥACD = 2x , 則 ㄥDBC = ㄥCDB = ㄥBCA = x在 △BCD 中ㄥACD + ㄥDBC + ㄥCDB + ㄥBCA = 180° (△內角和)2x + x + x + x = 180°x = 36°ㄥAED = ㄥACD + ㄥCDB = 72° + 36° = 108° (△外角)
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110717000051KK00497