✔ 最佳答案
Use equation of motion: s = ut + (1/2)at^2
with s = -300 m, u = 13 m/s, a = -g (=-10 m/s^2), t = ?
hence, -300 = 13t + (1/2).(10)t^2
i.e. 5t^2 -13t -300 = 0
solve for t gives t = 9.15 s or - 6.55 s (rejected)
Therefore, it takes 9.15 s for the bag to reach the ground.