please solve this sum?
2011-07-12 8:27 am
divide 64 into two parts such that three times the greater part will be equal to five times the smaller one?
回答 (5)
2011-07-12 8:29 am
✔ 最佳答案
So:x + y = 64, and if x > y then:
3x = 5y, or 3x - 5y = 0
Solving this by multiplying the first equation by -3 and then adding the two equations together:
x = 40, y = 24.
2011-07-12 4:08 pm
let two be x and y.
then, x+y=64 ---------------- ( 1 )
and from question we get 3x=5y
or, 3x-5y=0 ---------- ( 2 )
from ( 1 ) and ( 2 ) solving we get the value of x and y 40 and 24
then, x+y=64 ---------------- ( 1 )
and from question we get 3x=5y
or, 3x-5y=0 ---------- ( 2 )
from ( 1 ) and ( 2 ) solving we get the value of x and y 40 and 24
2011-07-12 4:03 pm
let the number be x
than the other number is 64-x
greater one = 64-x
smaller one = x
3(64-x) = 5x
192-3x = 5x
8x=192
x=24
so the numbers are 24 , 40
the greater and smaller numbers can be reversed , but u get the same numbers as 24 and 40.
than the other number is 64-x
greater one = 64-x
smaller one = x
3(64-x) = 5x
192-3x = 5x
8x=192
x=24
so the numbers are 24 , 40
the greater and smaller numbers can be reversed , but u get the same numbers as 24 and 40.
2011-07-12 3:31 pm
Let the greater part be x and the other y
x + y = 64
3x=5y
Solving simultaneously, x= 40, y=24
x + y = 64
3x=5y
Solving simultaneously, x= 40, y=24
2011-07-12 3:30 pm
24
40
40
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