Can anyone help me solve the following :
It is given that :
圖片參考：http://imgcld.yimg.com/8/n/HA00656648/o/701107120096713873428060.jpg
Solve the following if
圖片參考：http://imgcld.yimg.com/8/n/HA00656648/o/701107120096713873428061.jpg
圖片參考：http://imgcld.yimg.com/8/n/HA00656648/o/701107120096713873428072.jpg
THX A LOT !~
Maths --- trigo (urgent)
2011-07-13 3:01 am
回答 (1)
2011-07-13 3:15 am
✔ 最佳答案
(1 + 2sinβ cosβ) / (1 - 2sin²β) = 3/5(sin²β + cos²β + 2sinβ cosβ) / (sin²β + cos²β - 2sin²β) = 3/5(sinβ + cosβ)² / (cos²β - sin²β) = 3/5(You can skip the above steps)(sinβ + cosβ) / (cosβ - sinβ) = 3/5 5sinβ + 5cosβ = 3cosβ - 3sinβ8sinβ = - 2cosβsinβ / cosβ = - 2/8tan β = - 1/4β = 165.96376° or β = 345.96376° for 0° ≤ β < 360°
收錄日期: 2021-04-21 22:21:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110712000051KK00967