the enthalpy change
2011-07-12 11:41 pm
Sulphur has two allotropes, rhombic and monoclinic,both of which burn to form sulphur dioxide. The enthalpy of combustion ofrhombic sulphur is –296.6 kJ mol-1 and that of monoclinic sulphur if– 297 kJ mol-1. Calculate the enthalpy changefor the reaction. S(rhombic) ®S(monoclinic)
回答 (1)
2011-07-13 9:44 am
✔ 最佳答案
It is given that :S(rhombic) + O2(g) → SO2(g) ...ΔH = -296.6 kJ mol⁻¹
S(monoclinic) + O2(g) → SO2(g) ... ΔH = -297 kJ mol⁻¹
Then :
S(rhombic) + O2(g) → SO2(g) ... ΔH = -296.6 kJ mol⁻¹
SO2(g) → S(monoclinic) + O2(g)... ΔH = +297 kJ mol⁻¹
Add the above two thermochemical equation together, and cancel SO2(g)and O2(g) on the both sides. Hence,
S(rhombic) → S(monoclinic) ... ΔH = -296.6 + 297 = +0.4 kJ mol⁻¹
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