alkene + acidified potassium permanganate ---> diol
The book used ethene as example had gave a formula as below :
H2C=CH2 + [O] + H2O ----> CH2OHCH2OH
and said
[O] is from acidified KMnO4 as it is a strong oxidizing agent & H2O is from the KMnO4 solution
However, the book doesn't state the machanism or further explain; so, I have asked a question about this before, at
http://hk.knowledge.yahoo.com/question/question?qid=7011060600871
I have had a set of explanation.
However, recently, I have read a reference book(John McMurry's Organic Chemistry), it said that :
alkene + peroxyacid ----> epoxide + acid
圖片參考:http://imgcld.yimg.com/8/n/HA00656648/o/701107030037913873466760.jpg
and epoxide can undergo acid-catalyzed reaction with water to give diol,
圖片參考:http://imgcld.yimg.com/8/n/HA00656648/o/701107030037913873466771.jpg
The net result of alkene become diol is called hydroxylation.
Then, the book said that the hydroxylation can be carried out by treating with OsO4, osmium tetroxide. The cyclic osmate intermediate will then cleaved by NaHSO3(aq).
As I have seen in the previous question I asked, OsO4 seems to be able to be replaced by MnO4(-).
So, now, I want to ask :
1. Should the reaction of alkene with MnO4- to yield diol, be in a basic, acidic or neutral condition to carry out reaction?
Or, is alkene able to react with MnO4(-) in any aqueous conition as H3O(+) and OH(-) is present in any solution?
2. What is the reaction that really exist between alkene and MnO4(-) to yield diol, syn addition? Hydroxylation? Cleavage? Or others?
3. What is the condition for the reaction to take place?
更新1:
May you also tell me the machanism of the reaction? THX
更新2:
Thx a lot, but would you mind telling me the whole mechanism? the thing that I really want to know is the ''several steps'' THX a lot!~