✔ 最佳答案
the probability that "1" occurs exactly 3 times
=(6C3)((1/6)^3)((1-1/6)^3)
=625/11664
where 6C3 =6!/(3!*(6-3)!)
2011-07-03 15:43:39 補充:
yes, 6C3 means the number of combinations of three "1" and three non-"1" arrangement in six times throwing the dice