更新1:
what if replace x by 4 first and 1 second and then minus
What is the integration of (x+1/sqrt(x) ) ^2?
回答 (2)
2011-06-19 8:56 am
✔ 最佳答案
Ans: (x+1/sqrt(x) ) ^2 = x^2 + 2sqrt(x) + 1/xhence the integral is = (x^3)/3 + 4/3(x^(3/2)) + ln(x) + c
2011-06-19 3:38 pm
It's easiest to just expand:
= x^2 + 2sqrtx + 1/x
Integrate that gives
= x^3/3 +4x^(3/2)/3 + ln|x| + C
= x^2 + 2sqrtx + 1/x
Integrate that gives
= x^3/3 +4x^(3/2)/3 + ln|x| + C
收錄日期: 2021-05-01 00:54:29
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https://hk.answers.yahoo.com/question/index?qid=20110619002950AAzH0Ug