chemistry-gas volume

A gaseous mixture consistsof methane gas (CH4) and ethane gas (C2H6) in a mole ratio of 1:1. It has avolume of200 cm³ at room condition. What is the volume of oxygen required forthecomplete combustion of the mixture? (Hints：methaneand ethane will form CO2 and H2O during completecombustion) (Allvolume measured at room conditions)


Volume of CH4 = Volume of C2H6 = 200 x (1/2) =100 cm³

CH4 + 2O2 → CO2 + 2H2O
Volume of O2 reacted with CH4 = 100 x 2 = 200 cm³

2C2H6 + 7O2 → 4CO2+ 6H2O
Volume of O2 reacted with C2H6 = 100 x (7/2) =350 cm³

Total volume of O2 needed = 200 + 350 = 550cm³