a) [Al+3]= 0.60 M and [OH-1]= 1.80 M
b) [Al+3]= 0.60 M and [OH-1]= 0.60 M
c) [Al+3]= 1.80 M and [OH-1]= 0.60 M
d) [Al+3]= 0.60 M and [OH-1]= 0.20 M
When Al(OH)3 is dissolved in water to form a 0.60 M solution, the concentration of each ion in the solution is?
2011-06-18 12:39 am
回答 (3)
2011-06-18 11:40 am
a)
Let V be the volume of the solution.
No. of mole of Al(OH)3
= 0.6V mol
No. of mole of Al3+
=0.6V mol
No. of mole of OH-
=0.6X3XV
=1.8V mol
Molarity of Al3+
=0.6V/V
=0.6M
Molarity of OH-
=1.8V/V
=1.8M
Let V be the volume of the solution.
No. of mole of Al(OH)3
= 0.6V mol
No. of mole of Al3+
=0.6V mol
No. of mole of OH-
=0.6X3XV
=1.8V mol
Molarity of Al3+
=0.6V/V
=0.6M
Molarity of OH-
=1.8V/V
=1.8M
參考: Chemistry Textbook
2011-06-18 12:44 am
cghr
2011-06-18 12:43 am
a
收錄日期: 2021-04-20 00:53:19
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