更新1:
explanation!
How to find the derivative of sqrt(4-x^2)?
回答 (3)
2011-06-17 11:57 am
✔ 最佳答案
Method 1--------------
f (x) = ( 4 - x ² )^(1/2)
f ` (x) = (1/2) ( 4 - x ² )^(-1/2) (-2x)
f ` (x) = - x / ( 4 - x ² )^1/2)
Method 2
-------------
y = u^(1/2) where u = 4 - x ²
dy/du = (1/2) u^(-1/2) and du/dx = - 2x
dy/dx = (1/2) u^(-1/2) [ - 2x ]
dy/dx = - x / u^(1/2)
dy/dx= - x / ( 4 - x ² )^(1/2)
2011-06-17 6:25 pm
y = â(4 - x^2)
y = (4 - x^2)^1/2
dy/dx = 1/2(4 - x^2)^ -1/2 d/dx -2x
............x
= - -------------------- answer//
.......â(4 - x^2)
y = (4 - x^2)^1/2
dy/dx = 1/2(4 - x^2)^ -1/2 d/dx -2x
............x
= - -------------------- answer//
.......â(4 - x^2)
2011-06-17 6:17 pm
y=sqrt(4-x^2)
dy/dx=1/2*(4+x^2)^-1/2*2x
=x/sqrt(4-x^2)
dy/dx=1/2*(4+x^2)^-1/2*2x
=x/sqrt(4-x^2)
收錄日期: 2021-05-01 00:53:56
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