兩條f5math question ?10點
Find following indefinite integrals
a./(1/(3x+2)^1/2)dx
b./(u(u-1)^1/2)dx
回答 (2)
Find following indefinite integrals
a.
∫(1/(3x+2)^1/2)dx
= (1/3)∫(3x+2)^(-1/2)d(3x+2)
= (1/6)(3x+2)^(1/2) + C
b.
∫(u(u-1)^1/2)dx
= u(u-1)^(1/2) x + C
2011-06-10 19:33:38 補充:
∫(u(u-1)^(1/2)du
= (2/3) ∫ u d(u-1)^(3/2)
= (2/3) [u(u-1)^(3/2) - ∫(u-1)^(3/2)du]
= (2/3)[u(u-1)^(3/2) - ∫(u-1)^(3/2)d(u-1)]
= (2/3)[u(u-1)^(3/2) - (2/5)(u-1)^(5/2) + C1]
= 2u(u-1)^(3/2) /3 - 4(u-1)^(5/2) /15 + C2 for C2 = 2C1/3
參考: Hope the solution can help you^^”
收錄日期: 2021-04-23 20:44:25
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