化學平衡題目幫解

將2.50 mol NOCl置入1.50 L的容器中,溫度為400°C,平衡時有28.0%解離
2NOCl(g) ⇌ 2NO(g) +Cl2(g)試計算平衡常數Kc。


2NOCl(g) ⇌ 2NO(g) +Cl2(g)
[NOCl]o = 2.50/1.50 = 1.667 mol/L

平衡時：
NOCl 解離的濃度 = 1.667 * 28% = 0.467mol/L
[NOCl] = 1.667 - 0.467 = 1.2 mol/L
[NO] = 0.467 mol/L
[Cl2] = 0.467 * (1/2) = 0.234 mol/L

Kc = [NO]² [Cl2] / [NOCl]
= (0.467)² (0.234) / (1.2)²
= 0.0354 (mol/L)

2011-05-30 05:38:55 補充：
It should be: Kc = [NO]² [Cl2] / [NOCl]²