x^n + y^n = p!
(n>0)
更新1:
I Need a detail proofing!
Equation Solution
2011-05-27 6:11 am
Are there any four natural numbers x,y,n,p to fit the equation?
x^n + y^n = p!
(n>0)
x^n + y^n = p!
(n>0)
回答 (3)
2011-05-28 4:59 am
✔ 最佳答案
x = 12, y = 24, n = 2, p = 6or
x = 24, n = 2, p = 6
12^2 + 24^2 = 6!
144 + 576 = 720
720 = 720
or
24^2 + 12^2 = 6!
576 + 144 = 720
720 = 720
There may be more, just two examples
2011-06-09 06:53:17 補充：
Forget to stay the value of y in the second solution (y =12)
x = 24, y = 12, n = 2, p = 6
2011-05-28 12:25 am
Sorry, One situation should be added
x<>y<>n<>p
x<>y<>n<>p
2011-05-27 6:53 am
1^1 + 1^1 = 2!
x=y=n =1 ， p=2
所以答案是肯定的
x=y=n =1 ， p=2
所以答案是肯定的
收錄日期: 2021-04-29 16:56:58
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