F.5 app.of trigonometry

1 Let VQ = x, QS = 2xcos30 = √3xQR^2 = 3x^2/2cos theta = [QR^2 + VR^2 - VQ^2]/2(QR)(VR)= (3/2)/(√3√2)= 3/(2√6)= √6/4 (D)2 Let BF = xBE = x/sin40 = 1.5557xEF = x/tan40 = 1.1918xBC = x cos35 = 0.8192xBD = 1.4462xinclination of BE = arccos(BD/BE) = 22 (A)3 AC = 9/tan25 = 19.3BC = AC / cos38 = 24.492angle of elevation of P from B = arctan(PC/BC)= 20 (A)