A circuit
E = 36V
I1 = 6mA
V2 = 18V
R3 = 2k Ohm's
(1) The values of the resistors R1 and R2
(2) The voltage across the resistors R1 and R3
(3) Power dissipated by resistor R1, R2, R3
計算電路 電阻
2011-05-26 3:59 am
回答 (1)
2011-05-26 7:09 am
✔ 最佳答案
As you did not give the circuit, I presume all the three resistors are in connected series.(1) R2 = 18/6 kohms = 3 kohms
R1 = (36/6 - 3 - 2) kohms = 1 kohms
(2) voltage across R1 = 6 x 1 v = 6 v
voltage across R3 = 6 x 2 v = 12 v
(3) Power dissipated by R1 = 6^2/1 w = 36 mW = 0.036 w
Power dissipated by R2 = 18^2/3 108 mW = 0.108 w
Power dissipated by R3 = 12^2/2 mW = 72 mW = 0.072 w
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