Find the dy/dx for the following, show your steps, thx!~
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maths differentiation (urgent)
2011-05-22 9:20 am
回答 (2)
2011-05-22 10:35 am
✔ 最佳答案
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參考: miraco
2011-05-22 9:33 am
1.y=log(3) [x/(exp(4x)]
[x/exp(4x)]=3^y
y'*ln3=[exp(4x)-4xexp(4x)]/exp(8x)
y'=dy/dx=[exp(4x)-4xexp(4x)]/[ln3exp(8x)]
2.exp(sin(xy))=sin(x+y)
exp(sin(xy))*cos(xy)*(y+xy')=cos(x+y)*(1+y')
y'=dy/dx 再整理就行了
[x/exp(4x)]=3^y
y'*ln3=[exp(4x)-4xexp(4x)]/exp(8x)
y'=dy/dx=[exp(4x)-4xexp(4x)]/[ln3exp(8x)]
2.exp(sin(xy))=sin(x+y)
exp(sin(xy))*cos(xy)*(y+xy')=cos(x+y)*(1+y')
y'=dy/dx 再整理就行了
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110522000051KK00117