✔ 最佳答案
Proof
I will show it by contracdition, suppose f(x)≠x for all x in R------(*)
then we have f(x)>x for all x or f(x)<x for all x
Since if there are x', y' with x'<y' s.t f(x')>x' and f(y')<y'
then define g(x)=f(x)-x, g is continuous and g(y')<0, g(x')>0 by 中間值定理
there is x in (x',y') s.t g(x)=f(x)-x=0 contracdits (*)
so we may assume f(x)>x for all x
But we have f(x)>x=f(f(x))>f(x) this is impossible
So there exists a ξ in R such that f(ξ)=ξ
2011-05-22 20:43:57 補充:
以前想到
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