Given: f(-3)=1, f'(-3)=-2, f"(-3)=-1, further derivatives (start from third derivative) at x=-3 will be 0
Find f(x)
Thanks!!!!
F.6 Functions
2011-05-20 6:46 pm
回答 (1)
2011-05-20 8:18 pm
✔ 最佳答案
Since the value=0 for third derivative and onwards, it is asily observed that the function is a second degree function, i.e., f(x)=ax²+bx+cf(-3)=9a-3b+c=1-----(1)
f'(x)=2ax+b=>f'(-3)=-6a+b=-2-------(2)
f''(x)=2a=>a=-1/2
By substituting a=-1/2 in (1) and (2)
b=-5, c=-19/2
∴f(x)=(-1/2)x²-5x-19/2
收錄日期: 2021-04-23 20:10:43
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