✔ 最佳答案
Let X be the distribution of the score, X~N(62,7^2)
P( getting A)
=P( X >= 90)
=P(Z>= (90-62)/7 )
=P(Z>=4) ≒ 0
P(getting B or above)
=P( X >= 80)
=P(Z>= (80-62)/7 )
=P(Z>=2.57)
= 1- 0.9949 = 0.0051 = 0.51%
P(getting C or above)
=P( X >= 70)
=P(Z>= (70-62)/7 )
=P(Z>=1.14)
= 1- 0.8729 = 0.1271 = 12.71%
P(getting D or above)
=P( X >= 60)
=P(Z>= (60-62)/7 )
=P(Z>= - 0.29)
= 1- 0.3859 = 0.6141 = 61.41 %
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percentage of A = 0
percentage of B = 0.51%
percentage of C = 12.71% - 0.51% = 12.20%
percentage of D = 61.41% - 12.71 % = 48.70%
percentage of F = 100% - 61.41% = 38.59%