Mathematics homework~Help~!!

Q1.
It is given that Δ ABC ~ Δ XZY . If ∠A = 60° , AB = 5.5 cm, CA = 4.4 cm and XZ= 5 cm , find XY .

Δ ABC ~ Δ XZY
AB/XZ = CA/XY
(5.5 cm)/(5 cm) = (4.4 cm)/XY
XY = 4.4 * (5/5.5) cm
XY = 4 cm


= = = = =
Q2.
It is given that Δ ABC ~ Δ LMN . If 2BC = 3MN , LM = 6 , ∠L = 70° and ∠M = 60° , find AB .

2BC = 3MN
BC/MN = 3/2 ...... (1)

Δ ABC ~ Δ LMN
AB/LM = BC/MN
AB/6 = BC/MN ...... (2)

(2) = (1):
Ab/6 = 3/2
BC = 6*(3/2)
BC = 9