In how many ways can 4 couples be seated in a row if
a) all men must sit together. ans: 2880
b) all men must not sit together. ans: 37440
F5 Maths permutation
2011-05-10 9:19 pm
回答 (1)
2011-05-10 10:07 pm
✔ 最佳答案
(a) Treat 4 men as one, then the no. of ways = 5!Since, the men have 4! no. of ways to change their locations
Total no. of ways = 5! * 4! = 2880
(b) It is just the coplement of (a) and the no. of ways
= 8! - 2880
= 37440
收錄日期: 2021-04-26 19:17:38
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