請幫我化簡一條三角式,列步驟
4tanQ/cos(90度-Q) - 1/sin(90度-Q)
化簡三角式
2011-05-09 2:45 am
回答 (2)
2011-05-09 2:56 am
✔ 最佳答案
4tanQ/cos(90度-Q) - 1/sin(90度-Q)=4(sinQ/cosQ)/ sinQ- 1/cosQ
=(4sinQ/cosQ)*1/sinQ-1/cosQ
=4/cosQ-1/cosQ
=3/cosQ
參考: 自己
2011-05-09 2:56 am
4tanQ/cos(90度-Q) - 1/sin(90度-Q)
=4(sinQ/cosQ)(1/sinQ)-1/cosQ
=4/cosQ-1/cosQ
=3/cosQ
=4(sinQ/cosQ)(1/sinQ)-1/cosQ
=4/cosQ-1/cosQ
=3/cosQ
收錄日期: 2021-04-16 12:41:58
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110508000051KK01082