Integration ( trigo. sub.)
2011-05-09 1:06 am
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Which one is correct? Explain. (as they are different)
回答 (2)
2011-05-09 1:33 am
✔ 最佳答案
Both of the ans are correctSince you have used different subsitution,
so that you have the different results in indefinite integration
when you set up the upper bound./lower bound.
you can get the same ans!
Hope that I can help you
2011-05-09 2:15 am
Both are correct.
(d/dx)(-cos⁻¹x + C) = 1/√(1 - x²)
(d/dx)(sin⁻¹x + C) = 1/√(1 - x²)
(d/dx)(-cos⁻¹x + C) = 1/√(1 - x²)
(d/dx)(sin⁻¹x + C) = 1/√(1 - x²)
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