F.4 M2 Limits
回答 (2)
1. lim(x->π/2)_Cosx/(π-2x) 0/0 type
=lim(x-π/2)_-Sinx/(-2)
=(1/2)
2.lim(x->0)_[e^x-e^(-x)]/{x[e^x+e^(-x)]} 0/0 type
=lim(x->0)_[e^(x)+e^(-x)]/{x[e^x-e^(-x)]+[e^x+e^(-x)]}
=(1+1)/[0+(1+1)]
=1
收錄日期: 2021-04-23 20:44:00
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