1+(1+2)+(1+2+3)+…+(1+2+3+…+30)=1*30+2*29+3*28+…+29*2+30*1=Σ(k=1 to 30)_k*(31-k)=31Σ(k=1 to 30)_k-Σ(k=1 to 30)_k^2=31*(30*31/2)-30*31*61/6=14415-9455=4960
2011-05-05 22:42:30 補充:
1+(1+2)+(1+2+3)+…+(1+2+3+…+30)
=Σ{(k=1 to 30)_[Σ(w=1 to k)_w]}
=Σ[(k=1 to 30)_k(k+1)/2]
=(1/2)Σ(k=1 to 30)_k^2+(1/2)Σ(k=1 to 30)_k
=30*31*61/12+30*31/4
=4727.5+232.5
=4960