Geometric sequence

2011-05-05 5:12 am
Given a geometric sequence whose sum of the first 10 terms us 4 and whose sum from the 11th to the 30th is 48, find the sum from the 31st to the 60th term.

Please give detailed solution!

更新1:

* us --> is

回答 (1)

2011-05-05 7:59 am
✔ 最佳答案
SUM OF GEOMETRIC SEQUENCE

= a(r^n - 1)/(r - 1)

So,

a(r^10 - 1)/(r - 1) = 4...(1)

ar^10(r^20 - 1)/(r - 1) = 48...(2)

So, 4/(r^10 - 1) = 48/[r^10(r^20 - 1)]

r^10(r^10 + 1) = 12

r^10 = 3

sum from the 31st to the 60th

= ar^30(r^30 - 1)/(r - 1)

= 2*27*26

= 1404

=


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