A- maths(Differentiation)問題2

2011-04-30 1:41 am

回答 (1)

2011-04-30 2:13 am
✔ 最佳答案
3.

(-1, -5) is a point on the curve y = 2x² + 3x - 4

y' = 4x + 3

Slope of the required tangent
= y' at (-1, -5)
= 4(-1) + 3
= -1

Equation of the required tangent:
(y + 5)/(x + 1) = -1
y + 5 = -x - 1
x + y + 6 = 0
參考: miraco


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