✔ 最佳答案
1)
25 cm³ of HxA reacts with 25 cm³ of 0.2M NaOH to give Na2A. Find the molarity of HxA.
HxA + xNaOH → NaxA + xH2O
Since NaxA is Na2A, x = 2
H2A + 2NaOH → Na2A + 2H2O
Molar ratio H2A : NaOH = 1 : 2
No. of moles of NaOH = 0.2 x (25/1000) = 0.005 mol
No. of moles of H2A = 0.005 x (1/2) = 0.0025 mol
Molarity of H2A = 0.0025/(25/1000) = 0.1 M
= = = = =
2)
In the reaction between iron(II) ammonium sulphate and potassium manganate(VII) solution. 25cm³ of the Fe²⁺ solution reacted with 24.8 cm³ of 0.02M KMnO4 solution. What is the molarity of the iron(II) ammonium sulphate solution?
5Fe²⁺(aq) + MnO4⁻(aq) + 8H⁺(aq) → 5Fe³⁺(aq) + Mn²⁺(aq) + 4H2O(l)
mole ratio Fe²⁺ : MnO4⁻ = 5 : 1
No. of moles of KMnO4 = 0.02 x (24.8/1000) = 0.000496 mol
No. of moles of MnO4⁻ = 0.000496 mol
No. of moles of Fe²⁺ = 0.000496 x 5 = 0.00248 mol
No. of moles of Fe(NH3)2(SO4)2 = 0.00248 mol
Molarity of Fe(NH3)2(SO4)2 = 0.00248/(25/1000) = 0.0992 M
2011-04-30 14:03:24 補充:
In the topic of redox reaction, you should learn the half equation of MnO4^- acting as an oxidizing agent. It is
MnO4^-(aq) + 8H^+(aq) + 5e^- → Mn^2+(aq) + 4H2O
This is not neutralization.