Chemistry VA Calculation

2011-04-30 12:27 am
1)25cmcube of HxA reacts with 25cmcube of 0.2M NaOH to give Na2A. Find the molarity of HxA. (HxA=x hydrogen ion; A is an unknown chemical)

2) In the reaction between iron(II) ammonium sulphate and potassium manganate(VII) solution. 25cmcube of the Fe2+ solution reacted with 24.8cmcube of 0.02M KMnO4 solution. What is the molarity of the iron(II) ammonium sulphate solution?
更新1:

Sioieng: Thank you for your answering. But for Q.2, I wonder why there is hydrogen ion on the left-handed side of the equation and finally H2O produces. Is it the neutralization? Thz

回答 (4)

2011-04-30 1:07 am
✔ 最佳答案
1)
25 cm³ of HxA reacts with 25 cm³ of 0.2M NaOH to give Na2A. Find the molarity of HxA.

HxA + xNaOH → NaxA + xH2O
Since NaxA is Na2A, x = 2

H2A + 2NaOH → Na2A + 2H2O
Molar ratio H2A : NaOH = 1 : 2

No. of moles of NaOH = 0.2 x (25/1000) = 0.005 mol
No. of moles of H2A = 0.005 x (1/2) = 0.0025 mol
Molarity of H2A = 0.0025/(25/1000) = 0.1 M


= = = = =
2)
In the reaction between iron(II) ammonium sulphate and potassium manganate(VII) solution. 25cm³ of the Fe²⁺ solution reacted with 24.8 cm³ of 0.02M KMnO4 solution. What is the molarity of the iron(II) ammonium sulphate solution?

5Fe²⁺(aq) + MnO4⁻(aq) + 8H⁺(aq) → 5Fe³⁺(aq) + Mn²⁺(aq) + 4H2O(l)
mole ratio Fe²⁺ : MnO4­⁻ = 5 : 1

No. of moles of KMnO4­ = 0.02 x (24.8/1000) = 0.000496 mol
No. of moles of MnO4⁻ = 0.000496 mol
No. of moles of Fe²⁺ = 0.000496 x 5 = 0.00248 mol
No. of moles of Fe(NH3)2(SO4)2 = 0.00248 mol
Molarity of Fe(NH3)2(SO4)2 = 0.00248/(25/1000) = 0.0992 M

2011-04-30 14:03:24 補充:
In the topic of redox reaction, you should learn the half equation of MnO4^- acting as an oxidizing agent. It is
MnO4^-(aq) + 8H^+(aq) + 5e^- → Mn^2+(aq) + 4H2O

This is not neutralization.
參考: sioieng, sioieng
2011-04-30 2:21 am
note that the definition of neutralization is the reaction between acid and alkali to produce salt and water. Is there any reaction between acid and alkali? answer it yourself.

2011-04-29 18:22:26 補充:
the second hint: hydrogen ion is used for acidifying something else.
2011-04-30 1:44 am
shut up dumbass==

2011-04-29 17:48:34 補充:
Sioieng: Thank you for your answering. But for Q.2, I wonder why there is hydrogen ion on the left-handed side of the equation and finally H2O produces. Is it the neutralization? Thz

2011-04-29 18:52:17 補充:
acutally,i think iron(II) ammonium sulphate and potassium manganate are salt...so i am thinking of where is the hydrogen ion from....

2011-04-29 18:55:55 補充:
ammonium? is there something about dative covalent bond?btw, thx for your hints=]

2011-04-30 21:04:00 補充:
Redox reaction? it don't know what it is....Is it in NSS F4 syllabus?
2011-04-30 1:37 am
不要答他吧﹗不要助長問功課人士。


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