x² (x-1)²-4x(x-1)-12
連長細過程
F2因式分解急急急急急有10點
2011-04-28 7:52 pm
回答 (2)
2011-04-28 8:11 pm
✔ 最佳答案
設 y = x(x-1),
x² (x-1)²-4x(x-1)-12
= y² - 4y - 12
= (y-6)(y+2)
代回 y = x(x-1)
(y-6)(y+2)
= [x(x-1) - 6][x(x-1) + 2]
= (x²-x-6)(x²-x+2)
= (x-3)(x+2)(x²-x+2)
2011-04-28 10:32 pm
x^2*(x-1)^2-4x(x-1)-12
=(x(x-1))^2-2(2)(x(x-1))+4-12
=(x(x-1))-2)^2-12
=(x^2-x-2)^2-12
=(x-2)(x+1)-12
=(x(x-1))^2-2(2)(x(x-1))+4-12
=(x(x-1))-2)^2-12
=(x^2-x-2)^2-12
=(x-2)(x+1)-12
收錄日期: 2021-04-13 17:57:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110428000051KK00455