1/(sin2次θ)--cosθ/sinθ X tanθ
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中三數學問題(三角比)
2011-04-25 11:13 pm
回答 (1)
2011-04-26 12:11 am
✔ 最佳答案
1/(sin^2 θ)-cosθ/(sinθ * tanθ)= 1/sin^2 θ - cosθ/(sinθ * sinθ / cosθ)
= 1/sin^2 θ - cos^2 θ / sin^2 θ
= (1-cos^2 θ)/sin^2 θ
= sin^2 θ / sin^2 θ
= 1
參考: Hope the solution can help you^^”
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110425000051KK00790