Joint p.d.f.

回答 (1)

2011-04-25 10:50 pm
✔ 最佳答案
(i)

X = -1, 0, 4, 49
P(X) = 125/216,75/216,15/216,1/216

(ii)

E(X)

= (-125 + 4*15 + 49)/216

= -2/27

E(X^2)

= (125 + 16*15 + 49^2)/216

= 461/36

Var(X) = E(X^2) - [E(X)]^2 = 12.8

(iii) Y = -24, 0, 16, 2401

P(Y) = 125/216, 75/216, 15/216, 1/216


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