*要解釋/步驟...THX:)*
更新1:
Question link : http://img862.imageshack.us/img862/9121/001bz.jpg
Maths F4...7
2011-04-24 8:08 am
Question link : http://img862.imageshack.us/img862/9121/001bz.jpg
*要解釋/步驟...THX:)*
*要解釋/步驟...THX:)*
回答 (2)
2011-04-24 8:26 am
2011-04-24 8:27 am
24 logx + log(2x - 7)/log(x - 2) = 2log[x(2x - 7)] = log[(x - 2)^2]2x^2 - 7x = x^2 - 4x + 4x^2 - 3x - 4 = 0x = -1 (rejected) or 425(a) 4^(x + 1) = 4*4^x = 4y^24y^2 - 7(2y) - 8 = 02y^2 - 7y - 4 = 0(2y + 1)(y - 4) = 0y = -1/2 (rejected) or 4x = 2
收錄日期: 2021-04-23 20:44:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110424000051KK00012