Factorize :
ab^2 - 2c + 2b + ac - abc - ab + 2bc - 2b^2
factorization
2011-04-23 4:01 pm
回答 (1)
2011-04-23 4:46 pm
✔ 最佳答案
ab^2 - 2c + 2b + ac - abc - ab + 2bc - 2b^2 = (ab^2 - 2b^2) + ( ac - 2c) -(abc-2bc)-(ab-2b)
= b^2(a-2) +c(a-2) -bc(a-2)-b(a-2)
=(a-2)(b^2 +c -bc-b)
= (a-2)[b(b-c) -(b-c)]
= (a-2)(b-c)(b-1)
收錄日期: 2021-04-13 17:57:10
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110423000051KK00222