properties of circle (f.4)

2011-04-21 4:36 pm

回答 (1)

2011-04-21 4:57 pm
✔ 最佳答案
∠RTS = 90° (∠ in semi-circle)
∠TRS + ∠TSR + ∠RTS = 180° (∠ sum of ∆)
x + ∠TSR + 90° = 180°
Hence, ∠TSR = 90° - x

Since ∠s in segment subtends arcs in ratio,
∠TRS/(arc TS) = ∠TSR/(arc TR)
x/2 = (90° - x)/3
3x = 180° - 2x
x = 36°

Similarly, ∠TRS/(arc TS) = ∠QRS/(arc QS)
36°/2 = 72°/y
y = 4
參考: miraco


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