✔ 最佳答案
ㄥBCC' = ㄥWBB' = 90+25 = 115°
DC / CC' = tan18°
CC' = DC / tan18° = 6 / tan18°
BC' ² = BC² + CC' ² - 2 BC CC' cos ㄥBCC'
BC' ² = 10² + (6/tan18°)² - 2 * 10 * 6/tan18° cos115°
BC' = 24.4352
Let x be the angle of elevation of A from C' :
tan x = AB/BC'
tan x = 6 / 24.4352
x = 13.8°