簡單微積分-三角

cos2x = 1 - 2(sinx)^2

∫ (sinx)^2 dx

= (1/2) ∫ (1 - cos2x) dx

= (1/2)(x - sin2x/2)

= x/2 + sin2x/4 + C

∫sin^2 X dx
=-(1/3)xcos^3X+C
這是送分嗎?
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