數學ratio唔識做
2011-04-14 3:08 am
回答 (2)
2011-04-15 6:24 am
when dg:gc:dc=1:2:3
area of rectangle ABCD:area of rectangle EFGD
=(3/1)^2
=9:1
so area of hexagon ABCGFE=8
area of rectangle EFGD:area of hexagon ABCGFE=1/9
area of rectangle ABCD:area of rectangle EFGD
=(3/1)^2
=9:1
so area of hexagon ABCGFE=8
area of rectangle EFGD:area of hexagon ABCGFE=1/9
2011-04-14 3:29 am
因為similar rect,所以 area of rect ABCD: area of rect EFGD
= DG+GC : DG
= (2+1)x(2+1) : 1x1
= 9 :1 (因為係area，所以要平方)
因為 ABCGFE = ABCD-EFGD
所以 area of EFGD : area of ABCGFE
= 1 : 9-1
= 1 : 8
= DG+GC : DG
= (2+1)x(2+1) : 1x1
= 9 :1 (因為係area，所以要平方)
因為 ABCGFE = ABCD-EFGD
所以 area of EFGD : area of ABCGFE
= 1 : 9-1
= 1 : 8
收錄日期: 2021-04-24 10:32:22
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110413000051KK00822