更新1:
AP and PB不是距離嗎?為什麼可用座標顯示?
equation of straight lines
2011-04-13 5:33 am
Given twopoints A(8, -3) and B(-1,3), find the coordinates of P on lines segemt AB suchthat AP:PB=2:1
回答 (2)
2011-04-13 6:53 am
2011-04-13 5:42 am
A(8,-3) B(-1,3)
--->
AB = (-1-8,3-(-3)) = (-9,6)
--->
AP = (-9,6)*2/3 (because the AP is a third of AB)
= (-6,4)
Therefore, coordinates of P are (8-6,-3+4)----> (2,1)
--->
AB = (-1-8,3-(-3)) = (-9,6)
--->
AP = (-9,6)*2/3 (because the AP is a third of AB)
= (-6,4)
Therefore, coordinates of P are (8-6,-3+4)----> (2,1)
參考: me
收錄日期: 2021-04-18 18:01:06
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110412000051KK01253